Optimal. Leaf size=75 \[ \frac{i \cos ^4(c+d x)}{4 a d}+\frac{\sin (c+d x) \cos ^3(c+d x)}{4 a d}+\frac{3 \sin (c+d x) \cos (c+d x)}{8 a d}+\frac{3 x}{8 a} \]
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Rubi [A] time = 0.128129, antiderivative size = 75, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.194, Rules used = {3092, 3090, 2635, 8, 2565, 30} \[ \frac{i \cos ^4(c+d x)}{4 a d}+\frac{\sin (c+d x) \cos ^3(c+d x)}{4 a d}+\frac{3 \sin (c+d x) \cos (c+d x)}{8 a d}+\frac{3 x}{8 a} \]
Antiderivative was successfully verified.
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Rule 3092
Rule 3090
Rule 2635
Rule 8
Rule 2565
Rule 30
Rubi steps
\begin{align*} \int \frac{\cos ^3(c+d x)}{a \cos (c+d x)+i a \sin (c+d x)} \, dx &=-\frac{i \int \cos ^3(c+d x) (i a \cos (c+d x)+a \sin (c+d x)) \, dx}{a^2}\\ &=-\frac{i \int \left (i a \cos ^4(c+d x)+a \cos ^3(c+d x) \sin (c+d x)\right ) \, dx}{a^2}\\ &=-\frac{i \int \cos ^3(c+d x) \sin (c+d x) \, dx}{a}+\frac{\int \cos ^4(c+d x) \, dx}{a}\\ &=\frac{\cos ^3(c+d x) \sin (c+d x)}{4 a d}+\frac{3 \int \cos ^2(c+d x) \, dx}{4 a}+\frac{i \operatorname{Subst}\left (\int x^3 \, dx,x,\cos (c+d x)\right )}{a d}\\ &=\frac{i \cos ^4(c+d x)}{4 a d}+\frac{3 \cos (c+d x) \sin (c+d x)}{8 a d}+\frac{\cos ^3(c+d x) \sin (c+d x)}{4 a d}+\frac{3 \int 1 \, dx}{8 a}\\ &=\frac{3 x}{8 a}+\frac{i \cos ^4(c+d x)}{4 a d}+\frac{3 \cos (c+d x) \sin (c+d x)}{8 a d}+\frac{\cos ^3(c+d x) \sin (c+d x)}{4 a d}\\ \end{align*}
Mathematica [A] time = 0.10056, size = 60, normalized size = 0.8 \[ \frac{8 \sin (2 (c+d x))+\sin (4 (c+d x))+4 i \cos (2 (c+d x))+i \cos (4 (c+d x))+12 c+12 d x}{32 a d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.115, size = 98, normalized size = 1.3 \begin{align*}{\frac{-{\frac{3\,i}{16}}\ln \left ( \tan \left ( dx+c \right ) -i \right ) }{ad}}-{\frac{{\frac{i}{8}}}{ad \left ( \tan \left ( dx+c \right ) -i \right ) ^{2}}}+{\frac{1}{4\,ad \left ( \tan \left ( dx+c \right ) -i \right ) }}+{\frac{{\frac{3\,i}{16}}\ln \left ( \tan \left ( dx+c \right ) +i \right ) }{ad}}+{\frac{1}{8\,ad \left ( \tan \left ( dx+c \right ) +i \right ) }} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: RuntimeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.467277, size = 159, normalized size = 2.12 \begin{align*} \frac{{\left (12 \, d x e^{\left (4 i \, d x + 4 i \, c\right )} - 2 i \, e^{\left (6 i \, d x + 6 i \, c\right )} + 6 i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i\right )} e^{\left (-4 i \, d x - 4 i \, c\right )}}{32 \, a d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 0.438954, size = 153, normalized size = 2.04 \begin{align*} \begin{cases} \frac{\left (- 512 i a^{2} d^{2} e^{8 i c} e^{2 i d x} + 1536 i a^{2} d^{2} e^{4 i c} e^{- 2 i d x} + 256 i a^{2} d^{2} e^{2 i c} e^{- 4 i d x}\right ) e^{- 6 i c}}{8192 a^{3} d^{3}} & \text{for}\: 8192 a^{3} d^{3} e^{6 i c} \neq 0 \\x \left (\frac{\left (e^{6 i c} + 3 e^{4 i c} + 3 e^{2 i c} + 1\right ) e^{- 4 i c}}{8 a} - \frac{3}{8 a}\right ) & \text{otherwise} \end{cases} + \frac{3 x}{8 a} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.12508, size = 134, normalized size = 1.79 \begin{align*} -\frac{\frac{6 i \, \log \left (i \, \tan \left (d x + c\right ) + 1\right )}{a} - \frac{6 i \, \log \left (i \, \tan \left (d x + c\right ) - 1\right )}{a} + \frac{2 \,{\left (3 \, \tan \left (d x + c\right ) + 5 i\right )}}{a{\left (-i \, \tan \left (d x + c\right ) + 1\right )}} + \frac{-9 i \, \tan \left (d x + c\right )^{2} - 26 \, \tan \left (d x + c\right ) + 21 i}{a{\left (\tan \left (d x + c\right ) - i\right )}^{2}}}{32 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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